A.
PERHITUNGAN
RELIABILITAS (METODA BELAH DUA)
Nama
Siswa
|
Skor
Ganjil
|
Skor
Genap
|
|||
X
|
Y
|
X2
|
Y2
|
XY
|
|
Asniri
|
5
|
4
|
25
|
16
|
20
|
Lintang
|
11
|
10
|
121
|
100
|
110
|
Frengki
|
7
|
3
|
49
|
9
|
21
|
Indah
|
9
|
8
|
81
|
64
|
72
|
Muhim Mudin
|
10
|
8
|
100
|
64
|
80
|
Nurul
|
4
|
6
|
16
|
36
|
24
|
Wahyudin
|
10
|
8
|
100
|
64
|
80
|
Heris
|
9
|
10
|
81
|
100
|
90
|
Ulfiani
|
4
|
9
|
16
|
81
|
36
|
Saptori
|
4
|
4
|
16
|
16
|
16
|
Aan
|
6
|
4
|
36
|
16
|
24
|
Yola
|
10
|
7
|
100
|
49
|
70
|
Sinta
|
6
|
8
|
26
|
64
|
48
|
Ade
|
9
|
9
|
81
|
81
|
81
|
Umi
|
7
|
8
|
49
|
64
|
56
|
= 111
|
= 106
|
2 = 897
|
2 = 824
|
Y
= 828
|
Setelah
dihitung/dijumlahkan diperolah harga-harga:
N = 15
= 111
= 106
2 = 897
2 = 824
Y = 828
Harga-harga tersebut di
atas dimasukkan ke dalam rumus Pearson’s Product Moment sebagai berikut:
N (
Y
) – (
) (
)
rxy =
{ N
(
2 ) – (
)2 } { N (
2
) – (
)2 }
15 (828) – (111) ( 106)
=
{ 15 (897) – (111)2
} { 15 (824) – (106)2 }
12.420 – 11.766
=
{13.455 – 12.321 } { 12.360 – 11.236 }
654
=
1.274.616
= 0.58
Berarti tes ini
tergolong baik sebab reliabilitasnya sedang.